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2532413145115 = 5772354661289
BaseRepresentation
bin100100110110011111100…
…101100000000000011011
322222002121020002221100201
4210312133211200000123
5312442340231120430
65215212522243031
7350650362365650
oct44663745400033
98862536087321
102532413145115
11896a99222a17
1234a970056477
13154a619b6149
148a7d87ddc27
1545d1950a8ca
hex24d9f96001b

2532413145115 has 8 divisors (see below), whose sum is σ = 3473023741920. Its totient is φ = 1736511870912.

The previous prime is 2532413145043. The next prime is 2532413145133. The reversal of 2532413145115 is 5115413142352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2532413145115 - 231 = 2530265661467 is a prime.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36177330610 + ... + 36177330679.

It is an arithmetic number, because the mean of its divisors is an integer number (434127967740).

Almost surely, 22532413145115 is an apocalyptic number.

2532413145115 is a deficient number, since it is larger than the sum of its proper divisors (940610596805).

2532413145115 is an equidigital number, since it uses as much as digits as its factorization.

2532413145115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72354661301.

The product of its digits is 72000, while the sum is 37.

Adding to 2532413145115 its reverse (5115413142352), we get a palindrome (7647826287467).

The spelling of 2532413145115 in words is "two trillion, five hundred thirty-two billion, four hundred thirteen million, one hundred forty-five thousand, one hundred fifteen".

Divisors: 1 5 7 35 72354661289 361773306445 506482629023 2532413145115