Search a number
-
+
253300110131 = 4332254925943
BaseRepresentation
bin1110101111100111011…
…1001111001100110011
3220012210220211211011102
43223321313033030303
513122224312011011
6312210420235015
724205004261045
oct3537167171463
9805726754142
10253300110131
11984733438a2
124111183ba6b
131ab699ac393
14c38cc19a95
1568c78de73b
hex3af9dcf333

253300110131 has 8 divisors (see below), whose sum is σ = 253906144800. Its totient is φ = 252694173312.

The previous prime is 253300110121. The next prime is 253300110157. The reversal of 253300110131 is 131011003352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 253300110131 - 26 = 253300110067 is a prime.

It is a super-2 number, since 2×2533001101312 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (253300110121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9750746 + ... + 9776688.

It is an arithmetic number, because the mean of its divisors is an integer number (31738268100).

Almost surely, 2253300110131 is an apocalyptic number.

253300110131 is a deficient number, since it is larger than the sum of its proper divisors (606034669).

253300110131 is a wasteful number, since it uses less digits than its factorization.

253300110131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48925.

The product of its (nonzero) digits is 270, while the sum is 20.

Adding to 253300110131 its reverse (131011003352), we get a palindrome (384311113483).

The spelling of 253300110131 in words is "two hundred fifty-three billion, three hundred million, one hundred ten thousand, one hundred thirty-one".

Divisors: 1 433 22549 25943 9763717 11233319 584988707 253300110131