Base | Representation |
---|---|
bin | 1110101111101000101… |
… | …1101011111011001111 |
3 | 220012211021221011102221 |
4 | 3223322023223323033 |
5 | 13122232200030141 |
6 | 312211131200211 |
7 | 24205100655331 |
oct | 3537213537317 |
9 | 805737834387 |
10 | 253305470671 |
11 | 984763752a0 |
12 | 411135a6067 |
13 | 1ab6ab382b6 |
14 | c38d813451 |
15 | 68c80ecbd1 |
hex | 3afa2ebecf |
253305470671 has 32 divisors (see below), whose sum is σ = 279530608896. Its totient is φ = 227634624000.
The previous prime is 253305470647. The next prime is 253305470713. The reversal of 253305470671 is 176074503352.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-253305470671 is a prime.
It is a super-2 number, since 2×2533054706712 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (253305470471) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 308532441 + ... + 308533261.
It is an arithmetic number, because the mean of its divisors is an integer number (8735331528).
Almost surely, 2253305470671 is an apocalyptic number.
253305470671 is a deficient number, since it is larger than the sum of its proper divisors (26225138225).
253305470671 is a wasteful number, since it uses less digits than its factorization.
253305470671 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1783.
The product of its (nonzero) digits is 529200, while the sum is 43.
The spelling of 253305470671 in words is "two hundred fifty-three billion, three hundred five million, four hundred seventy thousand, six hundred seventy-one".
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