Base | Representation |
---|---|
bin | 1110101111110100010… |
… | …0111010010000111101 |
3 | 220012221200022000220010 |
4 | 3223331010322100331 |
5 | 13122332112313140 |
6 | 312220024013433 |
7 | 24206230455231 |
oct | 3537504722075 |
9 | 805850260803 |
10 | 253354026045 |
11 | 984a08196aa |
12 | 41127901279 |
13 | 1ab77c08ca3 |
14 | c3960525c1 |
15 | 68cc4de880 |
hex | 3afd13a43d |
253354026045 has 16 divisors (see below), whose sum is σ = 405764274240. Its totient is φ = 134989536384.
The previous prime is 253354026007. The next prime is 253354026061. The reversal of 253354026045 is 540620453352.
It is not a de Polignac number, because 253354026045 - 213 = 253354017853 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 253354025994 and 253354026012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8272384 + ... + 8302953.
It is an arithmetic number, because the mean of its divisors is an integer number (25360267140).
Almost surely, 2253354026045 is an apocalyptic number.
It is an amenable number.
253354026045 is a deficient number, since it is larger than the sum of its proper divisors (152410248195).
253354026045 is a wasteful number, since it uses less digits than its factorization.
253354026045 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 16576364.
The product of its (nonzero) digits is 432000, while the sum is 39.
Adding to 253354026045 its reverse (540620453352), we get a palindrome (793974479397).
The spelling of 253354026045 in words is "two hundred fifty-three billion, three hundred fifty-four million, twenty-six thousand, forty-five".
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