Base | Representation |
---|---|
bin | 111001100111101000101111… |
… | …001111100010001110110011 |
3 | 1020020020222211120010220211200 |
4 | 321213220233033202032303 |
5 | 231203402200432000430 |
6 | 2254544023533342243 |
7 | 104243305551663603 |
oct | 7147505717421663 |
9 | 1206228746126750 |
10 | 253412453000115 |
11 | 738216882a6842 |
12 | 24509045937983 |
13 | ab528cbac1cb6 |
14 | 468132a144c03 |
15 | 1e46c8d23e460 |
hex | e67a2f3e23b3 |
253412453000115 has 96 divisors (see below), whose sum is σ = 447563561163264. Its totient is φ = 132614670182400.
The previous prime is 253412453000071. The next prime is 253412453000131. The reversal of 253412453000115 is 511000354214352.
253412453000115 is a `hidden beast` number, since 2 + 5 + 3 + 4 + 1 + 2 + 4 + 530 + 0 + 0 + 115 = 666.
It is not a de Polignac number, because 253412453000115 - 220 = 253412451951539 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 253412453000115.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 1093588765 + ... + 1093820465.
It is an arithmetic number, because the mean of its divisors is an integer number (4662120428784).
Almost surely, 2253412453000115 is an apocalyptic number.
253412453000115 is a deficient number, since it is larger than the sum of its proper divisors (194151108163149).
253412453000115 is a wasteful number, since it uses less digits than its factorization.
253412453000115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 233501 (or 233498 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
The spelling of 253412453000115 in words is "two hundred fifty-three trillion, four hundred twelve billion, four hundred fifty-three million, one hundred fifteen", and thus it is an aban number.
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