Base | Representation |
---|---|
bin | 100100111000000101111… |
… | …100011110010000101111 |
3 | 22222021000220111201121121 |
4 | 210320011330132100233 |
5 | 313004344343141221 |
6 | 5220055150041411 |
7 | 351041054235145 |
oct | 44700574362057 |
9 | 8867026451547 |
10 | 2534130443311 |
11 | 89779a630525 |
12 | 34b16b1a9267 |
13 | 154c7670b11c |
14 | 8a91c909595 |
15 | 45dba179a41 |
hex | 24e05f1e42f |
2534130443311 has 2 divisors, whose sum is σ = 2534130443312. Its totient is φ = 2534130443310.
The previous prime is 2534130443249. The next prime is 2534130443347. The reversal of 2534130443311 is 1133440314352.
2534130443311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2534130443311 - 237 = 2396691489839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2534130443381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267065221655 + 1267065221656.
It is an arithmetic number, because the mean of its divisors is an integer number (1267065221656).
Almost surely, 22534130443311 is an apocalyptic number.
2534130443311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2534130443311 is an equidigital number, since it uses as much as digits as its factorization.
2534130443311 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 34.
Adding to 2534130443311 its reverse (1133440314352), we get a palindrome (3667570757663).
The spelling of 2534130443311 in words is "two trillion, five hundred thirty-four billion, one hundred thirty million, four hundred forty-three thousand, three hundred eleven".
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