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2534130443311 is a prime number
BaseRepresentation
bin100100111000000101111…
…100011110010000101111
322222021000220111201121121
4210320011330132100233
5313004344343141221
65220055150041411
7351041054235145
oct44700574362057
98867026451547
102534130443311
1189779a630525
1234b16b1a9267
13154c7670b11c
148a91c909595
1545dba179a41
hex24e05f1e42f

2534130443311 has 2 divisors, whose sum is σ = 2534130443312. Its totient is φ = 2534130443310.

The previous prime is 2534130443249. The next prime is 2534130443347. The reversal of 2534130443311 is 1133440314352.

2534130443311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2534130443311 - 237 = 2396691489839 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2534130443381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1267065221655 + 1267065221656.

It is an arithmetic number, because the mean of its divisors is an integer number (1267065221656).

Almost surely, 22534130443311 is an apocalyptic number.

2534130443311 is a deficient number, since it is larger than the sum of its proper divisors (1).

2534130443311 is an equidigital number, since it uses as much as digits as its factorization.

2534130443311 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 34.

Adding to 2534130443311 its reverse (1133440314352), we get a palindrome (3667570757663).

The spelling of 2534130443311 in words is "two trillion, five hundred thirty-four billion, one hundred thirty million, four hundred forty-three thousand, three hundred eleven".