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253415450030339 is a prime number
BaseRepresentation
bin111001100111101011100001…
…111000010011000100000011
31020020021021120102120211102002
4321213223201320103010003
5231203424320201432324
62254545241154214215
7104243443043220212
oct7147534170230403
91206237512524362
10253415450030339
1173822986018a23
122450974158436b
13ab52c889a686c
1446815321b7079
151e46db63e83ae
hexe67ae1e13103

253415450030339 has 2 divisors, whose sum is σ = 253415450030340. Its totient is φ = 253415450030338.

The previous prime is 253415450030293. The next prime is 253415450030363. The reversal of 253415450030339 is 933030054514352.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 253415450030339 - 212 = 253415450026243 is a prime.

It is a super-3 number, since 3×2534154500303393 (a number of 44 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 253415450030293 and 253415450030302.

It is not a weakly prime, because it can be changed into another prime (253415450030389) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126707725015169 + 126707725015170.

It is an arithmetic number, because the mean of its divisors is an integer number (126707725015170).

Almost surely, 2253415450030339 is an apocalyptic number.

253415450030339 is a deficient number, since it is larger than the sum of its proper divisors (1).

253415450030339 is an equidigital number, since it uses as much as digits as its factorization.

253415450030339 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2916000, while the sum is 47.

The spelling of 253415450030339 in words is "two hundred fifty-three trillion, four hundred fifteen billion, four hundred fifty million, thirty thousand, three hundred thirty-nine".