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253420033047 = 3583914467091
BaseRepresentation
bin1110110000000100000…
…0101101010000010111
3220020010021111112110220
43230001000231100113
513123001012024142
6312230342445423
724210661511406
oct3540100552027
9806107445426
10253420033047
1198525002745
1241145a33873
131ab887aa19c
14c3a0b1563d
1568d31cc2ec
hex3b0102d417

253420033047 has 8 divisors (see below), whose sum is σ = 337951269120. Its totient is φ = 168917742840.

The previous prime is 253420033043. The next prime is 253420033049. The reversal of 253420033047 is 740330024352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 253420033047 - 22 = 253420033043 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253420032999 and 253420033017.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253420033043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7216029 + ... + 7251062.

It is an arithmetic number, because the mean of its divisors is an integer number (42243908640).

Almost surely, 2253420033047 is an apocalyptic number.

253420033047 is a deficient number, since it is larger than the sum of its proper divisors (84531236073).

253420033047 is a wasteful number, since it uses less digits than its factorization.

253420033047 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14472933.

The product of its (nonzero) digits is 60480, while the sum is 33.

Adding to 253420033047 its reverse (740330024352), we get a palindrome (993750057399).

The spelling of 253420033047 in words is "two hundred fifty-three billion, four hundred twenty million, thirty-three thousand, forty-seven".

Divisors: 1 3 5839 17517 14467091 43401273 84473344349 253420033047