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2534201403 = 31018363701
BaseRepresentation
bin1001011100001100…
…1101100000111011
320112121112202210020
42113003031200323
520142223421103
61055244421523
7116541233166
oct22703154073
96477482706
102534201403
111090544028
125a88478a3
13315045876
141a07d4add
15ec734753
hex970cd83b

2534201403 has 8 divisors (see below), whose sum is σ = 3412390416. Its totient is φ = 1672740000.

The previous prime is 2534201381. The next prime is 2534201429. The reversal of 2534201403 is 3041024352.

2534201403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 2534201403 - 29 = 2534200891 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2534201443) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4181548 + ... + 4182153.

It is an arithmetic number, because the mean of its divisors is an integer number (426548802).

Almost surely, 22534201403 is an apocalyptic number.

2534201403 is a deficient number, since it is larger than the sum of its proper divisors (878189013).

2534201403 is a wasteful number, since it uses less digits than its factorization.

2534201403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8363805.

The product of its (nonzero) digits is 2880, while the sum is 24.

The square root of 2534201403 is about 50340.8522275895. The cubic root of 2534201403 is about 1363.3699233502.

Adding to 2534201403 its reverse (3041024352), we get a palindrome (5575225755).

The spelling of 2534201403 in words is "two billion, five hundred thirty-four million, two hundred one thousand, four hundred three".

Divisors: 1 3 101 303 8363701 25091103 844733801 2534201403