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25343144134349 is a prime number
BaseRepresentation
bin1011100001100101010010…
…00110101000011011001101
310022201210002021210202210212
411300302221012220123031
511310210224344244344
6125522251340212205
75223660510552566
oct560625106503315
9108653067722725
1025343144134349
118090a70195578
122a1380783a065
13111ab04767782
14638886b1916d
152de3777b379e
hex170ca91a86cd

25343144134349 has 2 divisors, whose sum is σ = 25343144134350. Its totient is φ = 25343144134348.

The previous prime is 25343144134333. The next prime is 25343144134369. The reversal of 25343144134349 is 94343144134352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24763860268900 + 579283865449 = 4976330^2 + 761107^2 .

It is a cyclic number.

It is not a de Polignac number, because 25343144134349 - 24 = 25343144134333 is a prime.

It is a super-2 number, since 2×253431441343492 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25343144134297 and 25343144134306.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25343144134369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12671572067174 + 12671572067175.

It is an arithmetic number, because the mean of its divisors is an integer number (12671572067175).

Almost surely, 225343144134349 is an apocalyptic number.

It is an amenable number.

25343144134349 is a deficient number, since it is larger than the sum of its proper divisors (1).

25343144134349 is an equidigital number, since it uses as much as digits as its factorization.

25343144134349 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7464960, while the sum is 50.

The spelling of 25343144134349 in words is "twenty-five trillion, three hundred forty-three billion, one hundred forty-four million, one hundred thirty-four thousand, three hundred forty-nine".