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25343513491 is a prime number
BaseRepresentation
bin10111100110100101…
…110101001110010011
32102102020021212201211
4113212211311032103
5403400414412431
615350451240551
71555015211302
oct274645651623
972366255654
1025343513491
11a82583087a
124ab35a9157
13250b75b13a
141325c46439
159d4e292b1
hex5e6975393

25343513491 has 2 divisors, whose sum is σ = 25343513492. Its totient is φ = 25343513490.

The previous prime is 25343513473. The next prime is 25343513509. The reversal of 25343513491 is 19431534352.

It is a balanced prime because it is at equal distance from previous prime (25343513473) and next prime (25343513509).

It is a cyclic number.

It is not a de Polignac number, because 25343513491 - 211 = 25343511443 is a prime.

It is a super-3 number, since 3×253435134913 (a number of 32 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (25343513431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12671756745 + 12671756746.

It is an arithmetic number, because the mean of its divisors is an integer number (12671756746).

Almost surely, 225343513491 is an apocalyptic number.

25343513491 is a deficient number, since it is larger than the sum of its proper divisors (1).

25343513491 is an equidigital number, since it uses as much as digits as its factorization.

25343513491 is an evil number, because the sum of its binary digits is even.

The product of its digits is 194400, while the sum is 40.

The spelling of 25343513491 in words is "twenty-five billion, three hundred forty-three million, five hundred thirteen thousand, four hundred ninety-one".