Base | Representation |
---|---|
bin | 1110110000001011110… |
… | …1000010001100000011 |
3 | 220020012112211100202001 |
4 | 3230002331002030003 |
5 | 13123032332442033 |
6 | 312233505204431 |
7 | 24211535522551 |
oct | 3540275021403 |
9 | 806175740661 |
10 | 253452624643 |
11 | 98541443249 |
12 | 41154930717 |
13 | 1ab9247b95a |
14 | c3a519abd1 |
15 | 68d5eb8e7d |
hex | 3b02f42303 |
253452624643 has 2 divisors, whose sum is σ = 253452624644. Its totient is φ = 253452624642.
The previous prime is 253452624641. The next prime is 253452624647. The reversal of 253452624643 is 346426254352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 253452624643 - 21 = 253452624641 is a prime.
Together with 253452624641, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 253452624593 and 253452624602.
It is not a weakly prime, because it can be changed into another prime (253452624641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126726312321 + 126726312322.
It is an arithmetic number, because the mean of its divisors is an integer number (126726312322).
Almost surely, 2253452624643 is an apocalyptic number.
253452624643 is a deficient number, since it is larger than the sum of its proper divisors (1).
253452624643 is an equidigital number, since it uses as much as digits as its factorization.
253452624643 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4147200, while the sum is 46.
Adding to 253452624643 its reverse (346426254352), we get a palindrome (599878878995).
The spelling of 253452624643 in words is "two hundred fifty-three billion, four hundred fifty-two million, six hundred twenty-four thousand, six hundred forty-three".
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