Base | Representation |
---|---|
bin | 1110110000010111011… |
… | …0110010101111010001 |
3 | 220020022221110100102011 |
4 | 3230011312302233101 |
5 | 13123132314221040 |
6 | 312242405022521 |
7 | 24212666445133 |
oct | 3540566625721 |
9 | 806287410364 |
10 | 253501320145 |
11 | 98566982967 |
12 | 411690b4a41 |
13 | 1ab9c59b368 |
14 | c3ab835053 |
15 | 68da3d73ea |
hex | 3b05db2bd1 |
253501320145 has 4 divisors (see below), whose sum is σ = 304201584180. Its totient is φ = 202801056112.
The previous prime is 253501320143. The next prime is 253501320151. The reversal of 253501320145 is 541023105352.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 63363461841 + 190137858304 = 251721^2 + 436048^2 .
It is a cyclic number.
It is not a de Polignac number, because 253501320145 - 21 = 253501320143 is a prime.
It is not an unprimeable number, because it can be changed into a prime (253501320143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25350132010 + ... + 25350132019.
It is an arithmetic number, because the mean of its divisors is an integer number (76050396045).
Almost surely, 2253501320145 is an apocalyptic number.
It is an amenable number.
253501320145 is a deficient number, since it is larger than the sum of its proper divisors (50700264035).
253501320145 is an equidigital number, since it uses as much as digits as its factorization.
253501320145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50700264034.
The product of its (nonzero) digits is 18000, while the sum is 31.
Adding to 253501320145 its reverse (541023105352), we get a palindrome (794524425497).
The spelling of 253501320145 in words is "two hundred fifty-three billion, five hundred one million, three hundred twenty thousand, one hundred forty-five".
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