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253530439117 is a prime number
BaseRepresentation
bin1110110000011110010…
…1110111110111001101
3220020101222020202010121
43230013211313313031
513123212243022432
6312245325104541
724213502114114
oct3540745676715
9806358222117
10253530439117
119858136142a
12411769b8151
131aba5625317
14c3b1654c7b
1568dcc3a197
hex3b07977dcd

253530439117 has 2 divisors, whose sum is σ = 253530439118. Its totient is φ = 253530439116.

The previous prime is 253530439111. The next prime is 253530439159. The reversal of 253530439117 is 711934035352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 235447182441 + 18083256676 = 485229^2 + 134474^2 .

It is a cyclic number.

It is not a de Polignac number, because 253530439117 - 23 = 253530439109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (253530439111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126765219558 + 126765219559.

It is an arithmetic number, because the mean of its divisors is an integer number (126765219559).

Almost surely, 2253530439117 is an apocalyptic number.

It is an amenable number.

253530439117 is a deficient number, since it is larger than the sum of its proper divisors (1).

253530439117 is an equidigital number, since it uses as much as digits as its factorization.

253530439117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 340200, while the sum is 43.

The spelling of 253530439117 in words is "two hundred fifty-three billion, five hundred thirty million, four hundred thirty-nine thousand, one hundred seventeen".