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253533914657 is a prime number
BaseRepresentation
bin1110110000011111001…
…1001000011000100001
3220020102012210022200022
43230013303020120201
513123214140232112
6312245531403225
724213543500642
oct3540763103041
9806365708608
10253533914657
1198583315681
1241177bb3515
131aba627125a
14c3b1cbb6c9
1568dd1c4d72
hex3b07cc8621

253533914657 has 2 divisors, whose sum is σ = 253533914658. Its totient is φ = 253533914656.

The previous prime is 253533914581. The next prime is 253533914677. The reversal of 253533914657 is 756419335352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 230562268561 + 22971646096 = 480169^2 + 151564^2 .

It is a cyclic number.

It is not a de Polignac number, because 253533914657 - 224 = 253517137441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 253533914599 and 253533914608.

It is not a weakly prime, because it can be changed into another prime (253533914677) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126766957328 + 126766957329.

It is an arithmetic number, because the mean of its divisors is an integer number (126766957329).

Almost surely, 2253533914657 is an apocalyptic number.

It is an amenable number.

253533914657 is a deficient number, since it is larger than the sum of its proper divisors (1).

253533914657 is an equidigital number, since it uses as much as digits as its factorization.

253533914657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 10206000, while the sum is 53.

The spelling of 253533914657 in words is "two hundred fifty-three billion, five hundred thirty-three million, nine hundred fourteen thousand, six hundred fifty-seven".