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253740145 = 5147134499
BaseRepresentation
bin11110001111111…
…00010001110001
3122200110100001011
433013330101301
51004424141040
641102310521
76200520121
oct1707742161
9580410034
10253740145
111202587aa
1270b88441
1340751bc9
14259b0c81
15174223ea
hexf1fc471

253740145 has 8 divisors (see below), whose sum is σ = 304704000. Its totient is φ = 202848240.

The previous prime is 253740143. The next prime is 253740161. The reversal of 253740145 is 541047352.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 253740145 - 21 = 253740143 is a prime.

It is a super-2 number, since 2×2537401452 = 128768122369242050, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (253740143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9895 + ... + 24604.

It is an arithmetic number, because the mean of its divisors is an integer number (38088000).

Almost surely, 2253740145 is an apocalyptic number.

It is an amenable number.

253740145 is a deficient number, since it is larger than the sum of its proper divisors (50963855).

253740145 is a wasteful number, since it uses less digits than its factorization.

253740145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 35975.

The product of its (nonzero) digits is 16800, while the sum is 31.

The square root of 253740145 is about 15929.2229879552. Note that the first 3 decimals coincide. The cubic root of 253740145 is about 633.0865124710.

Adding to 253740145 its reverse (541047352), we get a palindrome (794787497).

The spelling of 253740145 in words is "two hundred fifty-three million, seven hundred forty thousand, one hundred forty-five".

Divisors: 1 5 1471 7355 34499 172495 50748029 253740145