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253820943 = 321910314411
BaseRepresentation
bin11110010000100…
…00000000001111
3122200121102212200
433020100000033
51004434232233
641104132543
76201304515
oct1710200017
9580542780
10253820943
11120303482
1271007153
134077c90c
14259d24b5
151743b313
hexf21000f

253820943 has 24 divisors (see below), whose sum is σ = 389700480. Its totient is φ = 158740560.

The previous prime is 253820933. The next prime is 253820947. The reversal of 253820943 is 349028352.

It is not a de Polignac number, because 253820943 - 25 = 253820911 is a prime.

It is a super-2 number, since 2×2538209432 = 128850142210818498, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 253820898 and 253820907.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (253820947) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10408 + ... + 24818.

It is an arithmetic number, because the mean of its divisors is an integer number (16237520).

Almost surely, 2253820943 is an apocalyptic number.

253820943 is a deficient number, since it is larger than the sum of its proper divisors (135879537).

253820943 is a wasteful number, since it uses less digits than its factorization.

253820943 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14539 (or 14536 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 36.

The square root of 253820943 is about 15931.7589424395. The cubic root of 253820943 is about 633.1537028579.

The spelling of 253820943 in words is "two hundred fifty-three million, eight hundred twenty thousand, nine hundred forty-three".

Divisors: 1 3 9 19 57 103 171 309 927 1957 5871 14411 17613 43233 129699 273809 821427 1484333 2464281 4452999 13358997 28202327 84606981 253820943