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253850497 is a prime number
BaseRepresentation
bin11110010000101…
…11001110000001
3122200122221102021
433020113032001
51004441203442
641104521441
76201456625
oct1710271601
9580587367
10253850497
111203236aa
1271020281
13407901c4
14259dd185
1517444e67
hexf217381

253850497 has 2 divisors, whose sum is σ = 253850498. Its totient is φ = 253850496.

The previous prime is 253850483. The next prime is 253850501. The reversal of 253850497 is 794058352.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 253319056 + 531441 = 15916^2 + 729^2 .

It is a cyclic number.

It is not a de Polignac number, because 253850497 - 211 = 253848449 is a prime.

It is not a weakly prime, because it can be changed into another prime (253850407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126925248 + 126925249.

It is an arithmetic number, because the mean of its divisors is an integer number (126925249).

Almost surely, 2253850497 is an apocalyptic number.

It is an amenable number.

253850497 is a deficient number, since it is larger than the sum of its proper divisors (1).

253850497 is an equidigital number, since it uses as much as digits as its factorization.

253850497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 43.

The square root of 253850497 is about 15932.6864338692. The cubic root of 253850497 is about 633.1782759528.

It can be divided in two parts, 2538 and 50497, that added together give a palindrome (53035).

The spelling of 253850497 in words is "two hundred fifty-three million, eight hundred fifty thousand, four hundred ninety-seven".