Base | Representation |
---|---|
bin | 100100111101101011101… |
… | …011110010110000010011 |
3 | 22222211112012002100120110 |
4 | 210331223223302300103 |
5 | 313104142333023011 |
6 | 5222530511012403 |
7 | 351342563264616 |
oct | 44755353626023 |
9 | 8884465070513 |
10 | 2540132314131 |
11 | 89a29a519945 |
12 | 35036520a103 |
13 | 1556c1cb0589 |
14 | 8ad2ba8417d |
15 | 4611c031ba6 |
hex | 24f6baf2c13 |
2540132314131 has 16 divisors (see below), whose sum is σ = 3537901416960. Its totient is φ = 1618050888960.
The previous prime is 2540132314129. The next prime is 2540132314219. The reversal of 2540132314131 is 1314132310452.
It is not a de Polignac number, because 2540132314131 - 21 = 2540132314129 is a prime.
It is a super-2 number, since 2×25401323141312 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2540132314631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19749415 + ... + 19877616.
It is an arithmetic number, because the mean of its divisors is an integer number (221118838560).
Almost surely, 22540132314131 is an apocalyptic number.
2540132314131 is a deficient number, since it is larger than the sum of its proper divisors (997769102829).
2540132314131 is a wasteful number, since it uses less digits than its factorization.
2540132314131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39627986.
The product of its (nonzero) digits is 8640, while the sum is 30.
Adding to 2540132314131 its reverse (1314132310452), we get a palindrome (3854264624583).
The spelling of 2540132314131 in words is "two trillion, five hundred forty billion, one hundred thirty-two million, three hundred fourteen thousand, one hundred thirty-one".
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