Base | Representation |
---|---|
bin | 111001110000110001011010… |
… | …011000111111001010101011 |
3 | 1020022111000021021010201001112 |
4 | 321300301122120333022223 |
5 | 231244143403440422220 |
6 | 2300144250501140535 |
7 | 104336542010331065 |
oct | 7160613230771253 |
9 | 1208430237121045 |
10 | 254040242123435 |
11 | 73a43952954a59 |
12 | 245aa84b0ba74b |
13 | ab99b79a75331 |
14 | 46a3882d64735 |
15 | 1e58282a6b5c5 |
hex | e70c5a63f2ab |
254040242123435 has 4 divisors (see below), whose sum is σ = 304848290548128. Its totient is φ = 203232193698744.
The previous prime is 254040242123419. The next prime is 254040242123443. The reversal of 254040242123435 is 534321242040452.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 254040242123435 - 24 = 254040242123419 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 254040242123392 and 254040242123401.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25404024212339 + ... + 25404024212348.
It is an arithmetic number, because the mean of its divisors is an integer number (76212072637032).
Almost surely, 2254040242123435 is an apocalyptic number.
254040242123435 is a deficient number, since it is larger than the sum of its proper divisors (50808048424693).
254040242123435 is an equidigital number, since it uses as much as digits as its factorization.
254040242123435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 50808048424692.
The product of its (nonzero) digits is 921600, while the sum is 41.
Adding to 254040242123435 its reverse (534321242040452), we get a palindrome (788361484163887).
The spelling of 254040242123435 in words is "two hundred fifty-four trillion, forty billion, two hundred forty-two million, one hundred twenty-three thousand, four hundred thirty-five".
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