Base | Representation |
---|---|
bin | 111001110000110001011010… |
… | …011001010111011110011111 |
3 | 1020022111000021021022202122101 |
4 | 321300301122121113132133 |
5 | 231244143404002114012 |
6 | 2300144250503225531 |
7 | 104336542011224302 |
oct | 7160613231273637 |
9 | 1208430237282571 |
10 | 254040242223007 |
11 | 73a43952a12849 |
12 | 245aa84b1482a7 |
13 | ab99b79aab756 |
14 | 46a3882d8cb39 |
15 | 1e58282a8ad57 |
hex | e70c5a65779f |
254040242223007 has 2 divisors, whose sum is σ = 254040242223008. Its totient is φ = 254040242223006.
The previous prime is 254040242222969. The next prime is 254040242223017. The reversal of 254040242223007 is 700322242040452.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-254040242223007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254040242223017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127020121111503 + 127020121111504.
It is an arithmetic number, because the mean of its divisors is an integer number (127020121111504).
Almost surely, 2254040242223007 is an apocalyptic number.
254040242223007 is a deficient number, since it is larger than the sum of its proper divisors (1).
254040242223007 is an equidigital number, since it uses as much as digits as its factorization.
254040242223007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 215040, while the sum is 37.
Adding to 254040242223007 its reverse (700322242040452), we get a palindrome (954362484263459).
The spelling of 254040242223007 in words is "two hundred fifty-four trillion, forty billion, two hundred forty-two million, two hundred twenty-three thousand, seven".
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