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254040242225347 is a prime number
BaseRepresentation
bin111001110000110001011010…
…011001011000000011000011
31020022111000021021022212212001
4321300301122121120003003
5231244143404002202342
62300144250503244431
7104336542011234154
oct7160613231300303
91208430237285761
10254040242225347
1173a43952a14586
12245aa84b149717
13ab99b79aac836
1446a3882d8d92b
151e58282a8b8b7
hexe70c5a6580c3

254040242225347 has 2 divisors, whose sum is σ = 254040242225348. Its totient is φ = 254040242225346.

The previous prime is 254040242225333. The next prime is 254040242225353. The reversal of 254040242225347 is 743522242040452.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-254040242225347 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 254040242225297 and 254040242225306.

It is not a weakly prime, because it can be changed into another prime (254040242225377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127020121112673 + 127020121112674.

It is an arithmetic number, because the mean of its divisors is an integer number (127020121112674).

Almost surely, 2254040242225347 is an apocalyptic number.

254040242225347 is a deficient number, since it is larger than the sum of its proper divisors (1).

254040242225347 is an equidigital number, since it uses as much as digits as its factorization.

254040242225347 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4300800, while the sum is 46.

Adding to 254040242225347 its reverse (743522242040452), we get a palindrome (997562484265799).

The spelling of 254040242225347 in words is "two hundred fifty-four trillion, forty billion, two hundred forty-two million, two hundred twenty-five thousand, three hundred forty-seven".