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25404113 = 73629159
BaseRepresentation
bin110000011101…
…0001011010001
31202210122220002
41200322023101
523000412423
62304255345
7425634320
oct140721321
952718802
1025404113
1113381539
128611555
135356127
1435340b7
15236c228
hex183a2d1

25404113 has 4 divisors (see below), whose sum is σ = 29033280. Its totient is φ = 21774948.

The previous prime is 25404079. The next prime is 25404139. The reversal of 25404113 is 31140452.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 25404113 - 28 = 25403857 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (25404413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1814573 + ... + 1814586.

It is an arithmetic number, because the mean of its divisors is an integer number (7258320).

Almost surely, 225404113 is an apocalyptic number.

It is an amenable number.

25404113 is a deficient number, since it is larger than the sum of its proper divisors (3629167).

25404113 is an equidigital number, since it uses as much as digits as its factorization.

25404113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3629166.

The product of its (nonzero) digits is 480, while the sum is 20.

The square root of 25404113 is about 5040.2492993899. The cubic root of 25404113 is about 293.9688715558.

Adding to 25404113 its reverse (31140452), we get a palindrome (56544565).

The spelling of 25404113 in words is "twenty-five million, four hundred four thousand, one hundred thirteen".

Divisors: 1 7 3629159 25404113