25404411015113 has 4 divisors (see below), whose sum is σ = 27358596477828. Its totient is φ = 23450225552400.

The previous prime is 25404411015103. The next prime is 25404411015131. The reversal of 25404411015113 is 31151011440452.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10065219440329 + 15339191574784 = 3172573^2 + 3916528^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-25404411015113 is a prime.

It is a super-2 number, since 2×25404411015113² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 25404411015113.

It is not an unprimeable number, because it can be changed into a prime (25404411015103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 977092731338 + ... + 977092731363.

It is an arithmetic number, because the mean of its divisors is an integer number (6839649119457).

Almost surely, 2^{25404411015113} is an apocalyptic number.

It is an amenable number.

25404411015113 is a deficient number, since it is larger than the sum of its proper divisors (1954185462715).

25404411015113 is a wasteful number, since it uses less digits than its factorization.

25404411015113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1954185462714.

The product of its (nonzero) digits is 9600, while the sum is 32.

Adding to 25404411015113 its reverse (31151011440452), we get a palindrome (56555422455565).

The spelling of 25404411015113 in words is "twenty-five trillion, four hundred four billion, four hundred eleven million, fifteen thousand, one hundred thirteen".