254079000013 has 2 divisors, whose sum is σ = 254079000014. Its totient is φ = 254079000012.

The previous prime is 254078999971. The next prime is 254079000029. The reversal of 254079000013 is 310000970452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 253519299049 + 559700964 = 503507^2 + 23658^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-254079000013 is a prime.

It is a super-2 number, since 2×254079000013² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254079000073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127039500006 + 127039500007.

It is an arithmetic number, because the mean of its divisors is an integer number (127039500007).

Almost surely, 2^254079000013 is an apocalyptic number.

It is an amenable number.

254079000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

254079000013 is an equidigital number, since it uses as much as digits as its factorization.

254079000013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 254079000013 its reverse (310000970452), we get a palindrome (564079970465).

The spelling of 254079000013 in words is "two hundred fifty-four billion, seventy-nine million, thirteen", and thus it is an aban number.