Base | Representation |
---|---|
bin | 100100111110010110100… |
… | …100111100101011001111 |
3 | 22222220101100012010202011 |
4 | 210332112210330223033 |
5 | 313112131044040142 |
6 | 5223130135042051 |
7 | 351366452066431 |
oct | 44762644745317 |
9 | 8886340163664 |
10 | 2540851940047 |
11 | 89a629753503 |
12 | 350526210327 |
13 | 1557a8101a25 |
14 | 8ad9948a651 |
15 | 461602ce417 |
hex | 24f9693cacf |
2540851940047 has 2 divisors, whose sum is σ = 2540851940048. Its totient is φ = 2540851940046.
The previous prime is 2540851940023. The next prime is 2540851940111. The reversal of 2540851940047 is 7400491580452.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2540851940047 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2540851949047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1270425970023 + 1270425970024.
It is an arithmetic number, because the mean of its divisors is an integer number (1270425970024).
Almost surely, 22540851940047 is an apocalyptic number.
2540851940047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2540851940047 is an equidigital number, since it uses as much as digits as its factorization.
2540851940047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1612800, while the sum is 49.
The spelling of 2540851940047 in words is "two trillion, five hundred forty billion, eight hundred fifty-one million, nine hundred forty thousand, forty-seven".
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