2541135433 has 4 divisors (see below), whose sum is σ = 2603114388. Its totient is φ = 2479156480.

The previous prime is 2541135413. The next prime is 2541135451. The reversal of 2541135433 is 3345311452.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1225840144 + 1315295289 = 35012^2 + 36267^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2541135433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2541135395 and 2541135404.

It is not an unprimeable number, because it can be changed into a prime (2541135413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30989416 + ... + 30989497.

It is an arithmetic number, because the mean of its divisors is an integer number (650778597).

Almost surely, 2^2541135433 is an apocalyptic number.

It is an amenable number.

2541135433 is a deficient number, since it is larger than the sum of its proper divisors (61978955).

2541135433 is an equidigital number, since it uses as much as digits as its factorization.

2541135433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61978954.

The product of its digits is 21600, while the sum is 31.

The square root of 2541135433 is about 50409.6759858660. The cubic root of 2541135433 is about 1364.6122659055.

Adding to 2541135433 its reverse (3345311452), we get a palindrome (5886446885).

The spelling of 2541135433 in words is "two billion, five hundred forty-one million, one hundred thirty-five thousand, four hundred thirty-three".