Base | Representation |
---|---|
bin | 111001110010000110010110… |
… | …011010110010000111001111 |
3 | 1020022210201200020200201110122 |
4 | 321302012112122302013033 |
5 | 231302142144021243211 |
6 | 2300254212400055155 |
7 | 104346251035514102 |
oct | 7162062632620717 |
9 | 1208721606621418 |
10 | 254131443540431 |
11 | 73a795a375a456 |
12 | 246044623044bb |
13 | aba5652766a32 |
14 | 46a8055640739 |
15 | 1e5a81e6136db |
hex | e721966b21cf |
254131443540431 has 2 divisors, whose sum is σ = 254131443540432. Its totient is φ = 254131443540430.
The previous prime is 254131443540421. The next prime is 254131443540439. The reversal of 254131443540431 is 134045344131452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 254131443540431 - 242 = 249733397029327 is a prime.
It is a super-2 number, since 2×2541314435404312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254131443540439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127065721770215 + 127065721770216.
It is an arithmetic number, because the mean of its divisors is an integer number (127065721770216).
Almost surely, 2254131443540431 is an apocalyptic number.
254131443540431 is a deficient number, since it is larger than the sum of its proper divisors (1).
254131443540431 is an equidigital number, since it uses as much as digits as its factorization.
254131443540431 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1382400, while the sum is 44.
Adding to 254131443540431 its reverse (134045344131452), we get a palindrome (388176787671883).
The spelling of 254131443540431 in words is "two hundred fifty-four trillion, one hundred thirty-one billion, four hundred forty-three million, five hundred forty thousand, four hundred thirty-one".
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