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2541342013441 = 711171941437749
BaseRepresentation
bin100100111110110011110…
…010011011100000000001
322222221122111100110001121
4210332303302123200001
5313114132023412231
65223250523032241
7351414552461020
oct44766362334001
98887574313047
102541342013441
1189a86034a940
1235064236b681
131558557bc79a
148b0045ba8b7
154618d336311
hex24fb3c9b801

2541342013441 has 16 divisors (see below), whose sum is σ = 3354804432000. Its totient is φ = 1863780238080.

The previous prime is 2541342013439. The next prime is 2541342013453. The reversal of 2541342013441 is 1443102431452.

It is a cyclic number.

It is not a de Polignac number, because 2541342013441 - 21 = 2541342013439 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2541342013397 and 2541342013406.

It is not an unprimeable number, because it can be changed into a prime (2541342013421) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 970717566 + ... + 970720183.

It is an arithmetic number, because the mean of its divisors is an integer number (209675277000).

Almost surely, 22541342013441 is an apocalyptic number.

It is an amenable number.

2541342013441 is a deficient number, since it is larger than the sum of its proper divisors (813462418559).

2541342013441 is a wasteful number, since it uses less digits than its factorization.

2541342013441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1941437784.

The product of its (nonzero) digits is 46080, while the sum is 34.

Adding to 2541342013441 its reverse (1443102431452), we get a palindrome (3984444444893).

The spelling of 2541342013441 in words is "two trillion, five hundred forty-one billion, three hundred forty-two million, thirteen thousand, four hundred forty-one".

Divisors: 1 7 11 17 77 119 187 1309 1941437749 13590064243 21355815239 33004441733 149490706673 231031092131 363048859063 2541342013441