Base | Representation |
---|---|
bin | 1001011101111011… |
… | …0011000100101011 |
3 | 20120010011011212000 |
4 | 2113132303010223 |
5 | 20201101330011 |
6 | 1100103422043 |
7 | 116656553016 |
oct | 22736630453 |
9 | 6503134760 |
10 | 2541433131 |
11 | 1094633366 |
12 | 5ab154923 |
13 | 3166a83b3 |
14 | 1a175837d |
15 | ed1b2356 |
hex | 977b312b |
2541433131 has 8 divisors (see below), whose sum is σ = 3765086160. Its totient is φ = 1694288736.
The previous prime is 2541433121. The next prime is 2541433151. The reversal of 2541433131 is 1313341452.
It is a happy number.
It is not a de Polignac number, because 2541433131 - 225 = 2507878699 is a prime.
It is a super-4 number, since 4×25414331314 (a number of 39 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 94127153 = 2541433131 / (2 + 5 + 4 + 1 + 4 + 3 + 3 + 1 + 3 + 1).
It is a junction number, because it is equal to n+sod(n) for n = 2541433095 and 2541433104.
It is not an unprimeable number, because it can be changed into a prime (2541433121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47063550 + ... + 47063603.
It is an arithmetic number, because the mean of its divisors is an integer number (470635770).
Almost surely, 22541433131 is an apocalyptic number.
2541433131 is a deficient number, since it is larger than the sum of its proper divisors (1223653029).
2541433131 is an equidigital number, since it uses as much as digits as its factorization.
2541433131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94127162 (or 94127156 counting only the distinct ones).
The product of its digits is 4320, while the sum is 27.
The square root of 2541433131 is about 50412.6286856776. The cubic root of 2541433131 is about 1364.6655526468.
Adding to 2541433131 its reverse (1313341452), we get a palindrome (3854774583).
The spelling of 2541433131 in words is "two billion, five hundred forty-one million, four hundred thirty-three thousand, one hundred thirty-one".
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