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254213497 is a prime number
BaseRepresentation
bin11110010011011…
…11110101111001
3122201100101100201
433021233311321
51010034312442
641120402201
76204531136
oct1711576571
9581311321
10254213497
111205513aa
1271176361
13408894b5
1425a9558d
15174b77b7
hexf26fd79

254213497 has 2 divisors, whose sum is σ = 254213498. Its totient is φ = 254213496.

The previous prime is 254213467. The next prime is 254213527. The reversal of 254213497 is 794312452.

It is a balanced prime because it is at equal distance from previous prime (254213467) and next prime (254213527).

It can be written as a sum of positive squares in only one way, i.e., 159365376 + 94848121 = 12624^2 + 9739^2 .

It is a cyclic number.

It is not a de Polignac number, because 254213497 - 211 = 254211449 is a prime.

It is a super-4 number, since 4×2542134974 (a number of 35 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (254213437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127106748 + 127106749.

It is an arithmetic number, because the mean of its divisors is an integer number (127106749).

Almost surely, 2254213497 is an apocalyptic number.

It is an amenable number.

254213497 is a deficient number, since it is larger than the sum of its proper divisors (1).

254213497 is an equidigital number, since it uses as much as digits as its factorization.

254213497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60480, while the sum is 37.

The square root of 254213497 is about 15944.0740402195. The cubic root of 254213497 is about 633.4799420212.

The spelling of 254213497 in words is "two hundred fifty-four million, two hundred thirteen thousand, four hundred ninety-seven".