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2542300003 = 17149547059
BaseRepresentation
bin1001011110001000…
…0110101101100011
320120011210012222101
42113202012231203
520201312100003
61100134151231
7120000123235
oct22742065543
96504705871
102542300003
111095075691
125ab4b2517
1331691cb39
141a1902255
15ed2d411d
hex97886b63

2542300003 has 4 divisors (see below), whose sum is σ = 2691847080. Its totient is φ = 2392752928.

The previous prime is 2542300001. The next prime is 2542300021. The reversal of 2542300003 is 3000032452.

2542300003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2542300003 - 21 = 2542300001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2542300001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74773513 + ... + 74773546.

It is an arithmetic number, because the mean of its divisors is an integer number (672961770).

Almost surely, 22542300003 is an apocalyptic number.

2542300003 is a deficient number, since it is larger than the sum of its proper divisors (149547077).

2542300003 is a wasteful number, since it uses less digits than its factorization.

2542300003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 149547076.

The product of its (nonzero) digits is 720, while the sum is 19.

The square root of 2542300003 is about 50421.2257189371. The cubic root of 2542300003 is about 1364.8206955415.

Adding to 2542300003 its reverse (3000032452), we get a palindrome (5542332455).

The spelling of 2542300003 in words is "two billion, five hundred forty-two million, three hundred thousand, three".

Divisors: 1 17 149547059 2542300003