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254244443413 is a prime number
BaseRepresentation
bin1110110011001000100…
…1100101010100010101
3220022020201202220220011
43230302021211110111
513131143034142123
6312444232440221
724240262053232
oct3546211452425
9808221686804
10254244443413
11989083a6424
1241335b49071
131ac8a528a7c
14c43c3d6789
156930776e0d
hex3b32265515

254244443413 has 2 divisors, whose sum is σ = 254244443414. Its totient is φ = 254244443412.

The previous prime is 254244443399. The next prime is 254244443441. The reversal of 254244443413 is 314344442452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 163942390404 + 90302053009 = 404898^2 + 300503^2 .

It is a cyclic number.

It is not a de Polignac number, because 254244443413 - 29 = 254244442901 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254244443113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127122221706 + 127122221707.

It is an arithmetic number, because the mean of its divisors is an integer number (127122221707).

Almost surely, 2254244443413 is an apocalyptic number.

It is an amenable number.

254244443413 is a deficient number, since it is larger than the sum of its proper divisors (1).

254244443413 is an equidigital number, since it uses as much as digits as its factorization.

254244443413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 737280, while the sum is 40.

Adding to 254244443413 its reverse (314344442452), we get a palindrome (568588885865).

The spelling of 254244443413 in words is "two hundred fifty-four billion, two hundred forty-four million, four hundred forty-three thousand, four hundred thirteen".