Base | Representation |
---|---|
bin | 100101000000010111010… |
… | …010101000101011010111 |
3 | 100000002221211121002110111 |
4 | 211000113102220223113 |
5 | 313131041404303112 |
6 | 5224124315503451 |
7 | 351504123152302 |
oct | 45002722505327 |
9 | 10002854532414 |
10 | 2543011400407 |
11 | 8a0537703a95 |
12 | 350a29457b87 |
13 | 155a6060b01a |
14 | 8b1221b3b39 |
15 | 46239b8e5a7 |
hex | 250174a8ad7 |
2543011400407 has 2 divisors, whose sum is σ = 2543011400408. Its totient is φ = 2543011400406.
The previous prime is 2543011400329. The next prime is 2543011400411. The reversal of 2543011400407 is 7040041103452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2543011400407 - 239 = 1993255586519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2543011403407) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271505700203 + 1271505700204.
It is an arithmetic number, because the mean of its divisors is an integer number (1271505700204).
Almost surely, 22543011400407 is an apocalyptic number.
2543011400407 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543011400407 is an equidigital number, since it uses as much as digits as its factorization.
2543011400407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 2543011400407 its reverse (7040041103452), we get a palindrome (9583052503859).
The spelling of 2543011400407 in words is "two trillion, five hundred forty-three billion, eleven million, four hundred thousand, four hundred seven".
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