2543121307 has 4 divisors (see below), whose sum is σ = 2692716696. Its totient is φ = 2393525920.

The previous prime is 2543121299. The next prime is 2543121337. The reversal of 2543121307 is 7031213452.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2543121307 - 2³ = 2543121299 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2543121337) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 74797669 + ... + 74797702.

It is an arithmetic number, because the mean of its divisors is an integer number (673179174).

Almost surely, 2^2543121307 is an apocalyptic number.

2543121307 is a deficient number, since it is larger than the sum of its proper divisors (149595389).

2543121307 is a wasteful number, since it uses less digits than its factorization.

2543121307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 149595388.

The product of its (nonzero) digits is 5040, while the sum is 28.

The square root of 2543121307 is about 50429.3694884241. The cubic root of 2543121307 is about 1364.9676506621.

Adding to 2543121307 its reverse (7031213452), we get a palindrome (9574334759).

The spelling of 2543121307 in words is "two billion, five hundred forty-three million, one hundred twenty-one thousand, three hundred seven".