Base | Representation |
---|---|
bin | 111001110100111010110011… |
… | …111110110001001100001111 |
3 | 1020100111020211101012021002112 |
4 | 321310322303332301030033 |
5 | 231313331014014311143 |
6 | 2300523220121014235 |
7 | 104366250603221006 |
oct | 7164726376611417 |
9 | 1210436741167075 |
10 | 254325213041423 |
11 | 74043798576517 |
12 | 24635b1b32437b |
13 | abba9c30149b4 |
14 | 46b3598071c3d |
15 | 1e608b0abde18 |
hex | e74eb3fb130f |
254325213041423 has 2 divisors, whose sum is σ = 254325213041424. Its totient is φ = 254325213041422.
The previous prime is 254325213041261. The next prime is 254325213041479. The reversal of 254325213041423 is 324140312523452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 254325213041423 - 210 = 254325213040399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254325213044423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127162606520711 + 127162606520712.
It is an arithmetic number, because the mean of its divisors is an integer number (127162606520712).
Almost surely, 2254325213041423 is an apocalyptic number.
254325213041423 is a deficient number, since it is larger than the sum of its proper divisors (1).
254325213041423 is an equidigital number, since it uses as much as digits as its factorization.
254325213041423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 254325213041423 its reverse (324140312523452), we get a palindrome (578465525564875).
The spelling of 254325213041423 in words is "two hundred fifty-four trillion, three hundred twenty-five billion, two hundred thirteen million, forty-one thousand, four hundred twenty-three".
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