Base | Representation |
---|---|
bin | 1001011110010111… |
… | …1011010111101001 |
3 | 20120020200010121212 |
4 | 2113211323113221 |
5 | 20202041131441 |
6 | 1100211442505 |
7 | 120011465663 |
oct | 22745732751 |
9 | 6506603555 |
10 | 2543302121 |
11 | 109569a588 |
12 | 5ab8b6435 |
13 | 316bb0cc9 |
14 | 1a1ac3533 |
15 | ed430eeb |
hex | 9797b5e9 |
2543302121 has 2 divisors, whose sum is σ = 2543302122. Its totient is φ = 2543302120.
The previous prime is 2543302103. The next prime is 2543302199. The reversal of 2543302121 is 1212033452.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2542176400 + 1125721 = 50420^2 + 1061^2 .
It is a cyclic number.
It is not a de Polignac number, because 2543302121 - 214 = 2543285737 is a prime.
It is not a weakly prime, because it can be changed into another prime (2543302621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1271651060 + 1271651061.
It is an arithmetic number, because the mean of its divisors is an integer number (1271651061).
Almost surely, 22543302121 is an apocalyptic number.
It is an amenable number.
2543302121 is a deficient number, since it is larger than the sum of its proper divisors (1).
2543302121 is an equidigital number, since it uses as much as digits as its factorization.
2543302121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 23.
The square root of 2543302121 is about 50431.1622015595. The cubic root of 2543302121 is about 1364.9999992844. Note that the first 6 decimals are identical.
Adding to 2543302121 its reverse (1212033452), we get a palindrome (3755335573).
The spelling of 2543302121 in words is "two billion, five hundred forty-three million, three hundred two thousand, one hundred twenty-one".
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