25433113000000 has 392 divisors, whose sum is σ = 65773093093632. Its totient is φ = 9746400000000.

The previous prime is 25433112999991. The next prime is 25433113000007. The reversal of 25433113000000 is 31133452.

It is not an unprimeable number, because it can be changed into a prime (25433113000007) by changing a digit.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 3130995939 + ... + 3131004061.

Almost surely, 2^{25433113000000} is an apocalyptic number.

25433113000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 25433113000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32886546546816).

25433113000000 is an abundant number, since it is smaller than the sum of its proper divisors (40339980093632).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

25433113000000 is an frugal number, since it uses more digits than its factorization.

25433113000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8297 (or 8262 counting only the distinct ones).

The product of its (nonzero) digits is 1080, while the sum is 22.

Adding to 25433113000000 its reverse (31133452), we get a palindrome (25433144133452).

The spelling of 25433113000000 in words is "twenty-five trillion, four hundred thirty-three billion, one hundred thirteen million", and thus it is an aban number.