Base | Representation |
---|---|
bin | 111001110101001100100000… |
… | …100001101011000111010011 |
3 | 1020100120001212120211222021011 |
4 | 321311030200201223013103 |
5 | 231314133422241000313 |
6 | 2300540041401311351 |
7 | 104400522504545644 |
oct | 7165144041530723 |
9 | 1210501776758234 |
10 | 254344214000083 |
11 | 74050859076a39 |
12 | 24639742795557 |
13 | abbc7307298bc |
14 | 46b447b7b96cb |
15 | 1e61123c9793d |
hex | e7532086b1d3 |
254344214000083 has 2 divisors, whose sum is σ = 254344214000084. Its totient is φ = 254344214000082.
The previous prime is 254344214000077. The next prime is 254344214000147. The reversal of 254344214000083 is 380000412443452.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-254344214000083 is a prime.
It is not a weakly prime, because it can be changed into another prime (254344214000683) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127172107000041 + 127172107000042.
It is an arithmetic number, because the mean of its divisors is an integer number (127172107000042).
Almost surely, 2254344214000083 is an apocalyptic number.
254344214000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
254344214000083 is an equidigital number, since it uses as much as digits as its factorization.
254344214000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 368640, while the sum is 40.
The spelling of 254344214000083 in words is "two hundred fifty-four trillion, three hundred forty-four billion, two hundred fourteen million, eighty-three", and thus it is an aban number.
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