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25440121 = 73634303
BaseRepresentation
bin110000100001…
…0111101111001
31202212111021201
41201002331321
523003040441
62305134201
7426144310
oct141027571
952774251
1025440121
11133a65a3
12862a361
135369635
143543277
152377c31
hex1842f79

25440121 has 4 divisors (see below), whose sum is σ = 29074432. Its totient is φ = 21805812.

The previous prime is 25440091. The next prime is 25440167. The reversal of 25440121 is 12104452.

25440121 is nontrivially palindromic in base 13.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 25440121 - 215 = 25407353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (25440521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1817145 + ... + 1817158.

It is an arithmetic number, because the mean of its divisors is an integer number (7268608).

Almost surely, 225440121 is an apocalyptic number.

It is an amenable number.

25440121 is a deficient number, since it is larger than the sum of its proper divisors (3634311).

25440121 is an equidigital number, since it uses as much as digits as its factorization.

25440121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3634310.

The product of its (nonzero) digits is 320, while the sum is 19.

The square root of 25440121 is about 5043.8200800584. The cubic root of 25440121 is about 294.1076972893.

Adding to 25440121 its reverse (12104452), we get a palindrome (37544573).

The spelling of 25440121 in words is "twenty-five million, four hundred forty thousand, one hundred twenty-one".

Divisors: 1 7 3634303 25440121