Base | Representation |
---|---|
bin | 111001110110000011011000… |
… | …111111111111101011011111 |
3 | 1020100202200222111011022210212 |
4 | 321312003120333333223133 |
5 | 231321120114220444411 |
6 | 2301023105105523035 |
7 | 104405010025364132 |
oct | 7166033077775337 |
9 | 1210680874138725 |
10 | 254403143531231 |
11 | 740738492799a2 |
12 | 2464904a04347b |
13 | abc5162475866 |
14 | 46b726c01a219 |
15 | 1e6292254968b |
hex | e760d8fffadf |
254403143531231 has 2 divisors, whose sum is σ = 254403143531232. Its totient is φ = 254403143531230.
The previous prime is 254403143531221. The next prime is 254403143531267. The reversal of 254403143531231 is 132135341304452.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 254403143531231 - 218 = 254403143269087 is a prime.
It is a super-2 number, since 2×2544031435312312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (254403143531221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127201571765615 + 127201571765616.
It is an arithmetic number, because the mean of its divisors is an integer number (127201571765616).
Almost surely, 2254403143531231 is an apocalyptic number.
254403143531231 is a deficient number, since it is larger than the sum of its proper divisors (1).
254403143531231 is an equidigital number, since it uses as much as digits as its factorization.
254403143531231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 518400, while the sum is 41.
Adding to 254403143531231 its reverse (132135341304452), we get a palindrome (386538484835683).
The spelling of 254403143531231 in words is "two hundred fifty-four trillion, four hundred three billion, one hundred forty-three million, five hundred thirty-one thousand, two hundred thirty-one".
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