25440433 has 2 divisors, whose sum is σ = 25440434. Its totient is φ = 25440432.

The previous prime is 25440431. The next prime is 25440439. The reversal of 25440433 is 33404452.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14197824 + 11242609 = 3768^2 + 3353^2 .

It is a cyclic number.

It is not a de Polignac number, because 25440433 - 2¹ = 25440431 is a prime.

Together with 25440431, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 25440398 and 25440407.

It is not a weakly prime, because it can be changed into another prime (25440431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12720216 + 12720217.

It is an arithmetic number, because the mean of its divisors is an integer number (12720217).

Almost surely, 2^25440433 is an apocalyptic number.

It is an amenable number.

25440433 is a deficient number, since it is larger than the sum of its proper divisors (1).

25440433 is an equidigital number, since it uses as much as digits as its factorization.

25440433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5760, while the sum is 25.

The square root of 25440433 is about 5043.8510089018. The cubic root of 25440433 is about 294.1088996057.

Adding to 25440433 its reverse (33404452), we get a palindrome (58844885).

The spelling of 25440433 in words is "twenty-five million, four hundred forty thousand, four hundred thirty-three".