Search a number
-
+
254414513281 is a prime number
BaseRepresentation
bin1110110011110001001…
…0010110010010000001
3220022200120210100220011
43230330102112102001
513132020103411111
6312513145544521
724244425452605
oct3547422262201
9808616710804
10254414513281
11989953a6435
1241382aa5141
131acb6833b26
14c456c27505
15694066d021
hex3b3c496481

254414513281 has 2 divisors, whose sum is σ = 254414513282. Its totient is φ = 254414513280.

The previous prime is 254414513219. The next prime is 254414513303. The reversal of 254414513281 is 182315414452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 174556840000 + 79857673281 = 417800^2 + 282591^2 .

It is a cyclic number.

It is not a de Polignac number, because 254414513281 - 27 = 254414513153 is a prime.

It is a super-2 number, since 2×2544145132812 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (254414213281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127207256640 + 127207256641.

It is an arithmetic number, because the mean of its divisors is an integer number (127207256641).

Almost surely, 2254414513281 is an apocalyptic number.

It is an amenable number.

254414513281 is a deficient number, since it is larger than the sum of its proper divisors (1).

254414513281 is an equidigital number, since it uses as much as digits as its factorization.

254414513281 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 153600, while the sum is 40.

The spelling of 254414513281 in words is "two hundred fifty-four billion, four hundred fourteen million, five hundred thirteen thousand, two hundred eighty-one".