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254441110251253 is a prime number
BaseRepresentation
bin111001110110100110101111…
…111111100010011011110101
31020100220022222110020112112111
4321312212233333202123311
5231322230343211020003
62301052344332251021
7104410522623234022
oct7166465777423365
91210808873215474
10254441110251253
117408896151a662
1224654485010a71
13abc89031cab73
1446b9030548549
151e638e5797e6d
hexe769affe26f5

254441110251253 has 2 divisors, whose sum is σ = 254441110251254. Its totient is φ = 254441110251252.

The previous prime is 254441110251233. The next prime is 254441110251269. The reversal of 254441110251253 is 352152011144452.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 233477697120529 + 20963413130724 = 15279977^2 + 4578582^2 .

It is a cyclic number.

It is not a de Polignac number, because 254441110251253 - 229 = 254440573380341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (254441110251233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127220555125626 + 127220555125627.

It is an arithmetic number, because the mean of its divisors is an integer number (127220555125627).

Almost surely, 2254441110251253 is an apocalyptic number.

It is an amenable number.

254441110251253 is a deficient number, since it is larger than the sum of its proper divisors (1).

254441110251253 is an equidigital number, since it uses as much as digits as its factorization.

254441110251253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 192000, while the sum is 40.

The spelling of 254441110251253 in words is "two hundred fifty-four trillion, four hundred forty-one billion, one hundred ten million, two hundred fifty-one thousand, two hundred fifty-three".