25454014132 has 6 divisors (see below), whose sum is σ = 44544524738. Its totient is φ = 12727007064.

The previous prime is 25454014129. The next prime is 25454014139. The reversal of 25454014132 is 23141045452.

It can be written as a sum of positive squares in only one way, i.e., 23979761316 + 1474252816 = 154854^2 + 38396^2 .

It is a super-3 number, since 3×25454014132³ (a number of 32 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25454014094 and 25454014103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (25454014139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3181751763 + ... + 3181751770.

Almost surely, 2^25454014132 is an apocalyptic number.

It is an amenable number.

25454014132 is a deficient number, since it is larger than the sum of its proper divisors (19090510606).

25454014132 is a wasteful number, since it uses less digits than its factorization.

25454014132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6363503537 (or 6363503535 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 25454014132 its reverse (23141045452), we get a palindrome (48595059584).

The spelling of 25454014132 in words is "twenty-five billion, four hundred fifty-four million, fourteen thousand, one hundred thirty-two".