Base | Representation |
---|---|
bin | 1011100100111001011011… |
… | …10100111010110001001011 |
3 | 10100010200001212222202022101 |
4 | 11302130231310322301023 |
5 | 11314042004220312230 |
6 | 130050445220134231 |
7 | 5235132116540164 |
oct | 562345564726113 |
9 | 110120055882271 |
10 | 25457040010315 |
11 | 81252a7470991 |
12 | 2a318b3237377 |
13 | 112878612a414 |
14 | 6401ad4aa76b |
15 | 2e22e1914aca |
hex | 17272dd3ac4b |
25457040010315 has 4 divisors (see below), whose sum is σ = 30548448012384. Its totient is φ = 20365632008248.
The previous prime is 25457040010301. The next prime is 25457040010373. The reversal of 25457040010315 is 51301004075452.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 25457040010315 - 213 = 25457040002123 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2545704001027 + ... + 2545704001036.
It is an arithmetic number, because the mean of its divisors is an integer number (7637112003096).
Almost surely, 225457040010315 is an apocalyptic number.
25457040010315 is a deficient number, since it is larger than the sum of its proper divisors (5091408002069).
25457040010315 is an equidigital number, since it uses as much as digits as its factorization.
25457040010315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5091408002068.
The product of its (nonzero) digits is 84000, while the sum is 37.
Adding to 25457040010315 its reverse (51301004075452), we get a palindrome (76758044085767).
The spelling of 25457040010315 in words is "twenty-five trillion, four hundred fifty-seven billion, forty million, ten thousand, three hundred fifteen".
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