25471488011 has 2 divisors, whose sum is σ = 25471488012. Its totient is φ = 25471488010.

The previous prime is 25471487983. The next prime is 25471488013. The reversal of 25471488011 is 11088417452.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 25471488011 - 2¹⁸ = 25471225867 is a prime.

It is a super-2 number, since 2×25471488011² (a number of 22 digits) contains 22 as substring.

Together with 25471488013, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25471488011.

It is not a weakly prime, because it can be changed into another prime (25471488013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12735744005 + 12735744006.

It is an arithmetic number, because the mean of its divisors is an integer number (12735744006).

Almost surely, 2^25471488011 is an apocalyptic number.

25471488011 is a deficient number, since it is larger than the sum of its proper divisors (1).

25471488011 is an equidigital number, since it uses as much as digits as its factorization.

25471488011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 71680, while the sum is 41.

The spelling of 25471488011 in words is "twenty-five billion, four hundred seventy-one million, four hundred eighty-eight thousand, eleven".