254909443 has 2 divisors, whose sum is σ = 254909444. Its totient is φ = 254909442.

The previous prime is 254909429. The next prime is 254909467. The reversal of 254909443 is 344909452.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 254909443 - 2⁵ = 254909411 is a prime.

It is a zygodrome in base 2.

It is a junction number, because it is equal to n+sod(n) for n = 254909396 and 254909405.

It is not a weakly prime, because it can be changed into another prime (254909143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 127454721 + 127454722.

It is an arithmetic number, because the mean of its divisors is an integer number (127454722).

Almost surely, 2^254909443 is an apocalyptic number.

254909443 is a deficient number, since it is larger than the sum of its proper divisors (1).

254909443 is an equidigital number, since it uses as much as digits as its factorization.

254909443 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 40.

The square root of 254909443 is about 15965.8837212351. The cubic root of 254909443 is about 634.0574961042.

Subtracting 254909443 from its reverse (344909452), we obtain a palindrome (90000009).

The spelling of 254909443 in words is "two hundred fifty-four million, nine hundred nine thousand, four hundred forty-three".