Base | Representation |
---|---|
bin | 10111101111011010… |
… | …000011001111010101 |
3 | 2102210112121022111000 |
4 | 113233122003033111 |
5 | 404201300420432 |
6 | 15413253333513 |
7 | 1561462332042 |
oct | 275732031725 |
9 | 72715538430 |
10 | 25491420117 |
11 | a8a1273259 |
12 | 4b35037299 |
13 | 25332a6257 |
14 | 133b7481c9 |
15 | 9e2de357c |
hex | 5ef6833d5 |
25491420117 has 32 divisors (see below), whose sum is σ = 40035720960. Its totient is φ = 15974945280.
The previous prime is 25491420109. The next prime is 25491420161. The reversal of 25491420117 is 71102419452.
It is not a de Polignac number, because 25491420117 - 23 = 25491420109 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (25491420197) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 344017 + ... + 411497.
It is an arithmetic number, because the mean of its divisors is an integer number (1251116280).
Almost surely, 225491420117 is an apocalyptic number.
25491420117 is a gapful number since it is divisible by the number (27) formed by its first and last digit.
It is an amenable number.
25491420117 is a deficient number, since it is larger than the sum of its proper divisors (14544300843).
25491420117 is a wasteful number, since it uses less digits than its factorization.
25491420117 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 68330 (or 68324 counting only the distinct ones).
The product of its (nonzero) digits is 20160, while the sum is 36.
Adding to 25491420117 its reverse (71102419452), we get a palindrome (96593839569).
The spelling of 25491420117 in words is "twenty-five billion, four hundred ninety-one million, four hundred twenty thousand, one hundred seventeen".
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