Base | Representation |
---|---|
bin | 1011100101111011000010… |
… | …00110001011110110011111 |
3 | 10100021000222102110012011222 |
4 | 11302331201012023312133 |
5 | 11320131122014204434 |
6 | 130114552121003555 |
7 | 5240516652013436 |
oct | 562754106136637 |
9 | 110230872405158 |
10 | 25492259913119 |
11 | 813923015917a |
12 | 2a386a23235bb |
13 | 112bba9a864ac |
14 | 641b90c9a11d |
15 | 2e31a393172e |
hex | 172f6118bd9f |
25492259913119 has 2 divisors, whose sum is σ = 25492259913120. Its totient is φ = 25492259913118.
The previous prime is 25492259913061. The next prime is 25492259913139. The reversal of 25492259913119 is 91131995229452.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 25492259913119 - 28 = 25492259912863 is a prime.
It is a super-2 number, since 2×254922599131192 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25492259913139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12746129956559 + 12746129956560.
It is an arithmetic number, because the mean of its divisors is an integer number (12746129956560).
Almost surely, 225492259913119 is an apocalyptic number.
25492259913119 is a deficient number, since it is larger than the sum of its proper divisors (1).
25492259913119 is an equidigital number, since it uses as much as digits as its factorization.
25492259913119 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15746400, while the sum is 62.
The spelling of 25492259913119 in words is "twenty-five trillion, four hundred ninety-two billion, two hundred fifty-nine million, nine hundred thirteen thousand, one hundred nineteen".
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